So two or more players earn the same score at one of the Musical Chairs event? And you want to know how ties are resolved? Resolving the tie is based on the actual result of all three games that are played. Here are the criteria for resolving tie-breakers which is primarily used for ranking the leading players of the week. It will also be applied to the Musical Genie Tourney of Champions.
If two players earned the same score, and one has won three games and the other has won two, then the person who won three games becomes the winner of the tie-breaker. Similarly for a player who has won two games versus another who has won one.
The actual score that was earned is looked at. If one person has a 13 to something game and no one else does, the player with the 13 score wins the tie. Similarly, 12 to something game has precedence over 11 to something games. Ditto for 11 games versus 10 games.
Example: On November 19th, both euchreforhire and xxtacy each earned an overall score of 43. Is euchreforhire or xxtacy ranked first? In this case, euchreforhire had 11-3, 10-9 and 10-6 while xxtacy had 11-3, 11-9 and 10-7. Since xxtacy had two 11 score games and one 10 score game versus euchreforhire's one 11 and two 10 games, xxtacy is ranked higher than euchreforhire.
If there is still a tie after the first two criteria are handled, this applies to those who have lost a game or two. Basically, the person who earn more points in the game(s) that are lost takes precedence over the person who earned less.
Example: On November 19th, Kubball and LynnTEN earned 30 points. Kubball had a 10-8 game, a 6-13 game, and a 10-2 game. LynnTEN had 4-10, 10-7 and 10-3. Noting that each player won two games, criterion one doesn't resolve the tie. Also, both players had two 10-x games, number two does not resolve the tie-breaker. So, Kubball had six point in the game that was lost and LynnTEN had 4 points in the losing game, thus Kubball came out ahead of LynnTEN.
If criteria one through three do not settle the tie, the score of the opponent in the lost game is considered. The person who allowed their opponent the lowest winning score will win the tie.
Example: Player 5 had 11-8, 4-13, 10-7 and player 6 had 11-7, 10-8 and 4-11. Since the first three criteria don't apply, player 6 wins the tiebreaker because player 6 lost the last game 4-11 while player 5 lost the second game 4-13.
This rule applies to those who tied at the final round of the TOC in determining who earns a TOC ribbon. This rule does not apply to regular Musical Chairs event. Suppose three players win 10-8 in two games and lose one game 8-10 in the final round. Since the first 4 conditions do not resolve the tie-breaker, the higher two scores in the qualifying round will earn the TOC ribbon. Suppose a player wins all 3 games 10-8 in the final round, the TOC ribbon will be awarded to the winner and the player who earned the highest score in the qualifying round. In the case where there is still a tie in the qualifying round, the first 4 criteria will resolve the tie-breaker on the qualifying round score.
This rule applies to sorting the players on the leading players of the week. On October 1st at Table Two, eternalhope, CWoody and mrjay won two games 10-8. Because eternalhope won the first two games, eternalhope was ranked 26th in the leading players of the week. CWoody earned 27th for losing the second game and mrjay was awarded 28th for losing the first game. However all three players were declared tied for 4th on the winner's page.
For the reader's information, this rule has not yet been used to resolve how one player is ranked to another player should the above six criteria fails to resolve the tie. I am thinking of using a weighted coin to resolve this issue if I really have to. I haven't decided what to do with this when it comes to resolving the final round of the TOC.